b^2+2b^2-3b^2+b^2=(1+2-3+1)b^2

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Solution for b^2+2b^2-3b^2+b^2=(1+2-3+1)b^2 equation: 



b^2+2b^2-3b^2+b^2=(1+2-3+1)b^2

We move all terms to the left:

b^2+2b^2-3b^2+b^2-((1+2-3+1)b^2)=0

We add all the numbers together, and all the variables

b^2+2b^2-3b^2+b^2-(1b^2)=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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